In a constant magnetic field, the magnetic force acting on the ore particles depends on the factors

<

    The magnetic force acting on the ore particles in the magnetic field can be deduced and derived in the following manner.
Modern electromagnetic theory holds that the magnetic moment of a molecule in an object is generated by a molecular current, and the magnetic moment of the object is the vector sum of the molecular magnetic moment (or atomic magnetic moment). After the magnetic ore particles are magnetized in the magnetic field, the effect can be expressed by an equivalent elemental current, which is considered equivalent to the effect of a small current-carrying coil in the magnetic field. Therefore, the magnetic force of the magnetic ore particles moving in a non-uniform magnetic field is equivalent to the magnetic force of a small current-carrying coil. Therefore, the magnetic force of the current-carrying coil when it moves in a non-uniform magnetic field can be studied first, and then it can be extended to magnetic ore particles.
When a current carrying coil moving in a magnetic field, if the intensity of the current in the coils is constant, then the magnetic force of the work done
â–³ A constant equal to the current intensity in the coil and I is the product of the magnetic flux of coil increments (â–³ Ñ„) by, which is:

            △ A = I△ ф ( 4-13 )

If the area enclosed by this coil is S , it moves a small distance Δ l in the inhomogeneous magnetic field, the magnetic field strength of the coil before moving is H , and the magnetic field strength after moving is H + △H , as shown below. Shown.

    Then the work done by the magnetic force △ A is:

                                      △ A = I△ ф = I [ S ( H + △H ) —SH 〕= IS△H ( 4-14 )

Where IS is the magnetic moment of the coil, denoted by M , so:

â–³A
= M·△H
                          ( 4-15 )[next]

    More magnetic than F magnetic means that the magnetic field acts on 1 gram The magnetic force on the mass of the ore. It can be seen from the formula ( 4-20 ) that the magnitude of the specific magnetic force F m acting on the ore particles depends mainly on the fact that the F magnet is proportional to the specific magnetic susceptibility x of the ore particles, so the magnetic properties of the ore particles are stronger. The greater the magnetic force. The F magnet is in turn proportional to the product of the magnetic field gradient gr-adH and the magnetic field strength H at which the ore particles are located (the product of the two is also called the magnetic field force). It can be seen that the larger the magnetic field strength and the magnetic field gradient, the larger the magnetic force of the ore particles.
It should be noted that the derivation of the specific magnetic force is based on the assumption that the size of the ore particle is small and the magnetic field gradient value gradH is equal to a constant.

Our Half Round Roof Gutter Roll Forming Machine is fabricated from high quality material and components under professional testing. We are committed to provide world class roll forming machine for sale. We are known to be a commendable manufacturer,exporter,supplier factory. It is our hard work and dedication which has enabled us to win the trust of numerous buyers all over the world.

Half Round Roof Gutter Roll Forming Machine

Half Round Roof Gutter Roll Forming Machine,Half Round Gutter Roll Forming Machine,Half Round Gutter Machine ,Half Round Shape Forming Machine

Botou Kaiyite Cold Bending Machinery Co.,Ltd. , https://www.chinacoldbendingmachinery.com